= 65 x ( 121 + 11) - 35 x ( 17 + 115 ) 

= 65 x 132 - 35 x 132 

= ( 65 - 35) x 132 

= 30 x 132 

= 3960

65x121-35x17+11x65-115x35=3.960

\(65\cdot121-35\cdot17+11\cdot65-115\cdot35\)

\(=65\cdot\left(11+121\right)-35\cdot\left(115+17\right)\)

\(=65\cdot132+35\cdot132\)

\(=132\cdot\left(65+35\right)\)

\(=132\cdot100\)

\(=13200\)

    ( 3,5 x 10,25 + 10,25 x 6,5 ) +  (65 x 11 - 65 : 0,1 )

=  10,25 x ( 3,5 + 6,5 )              +  65 x ( 11 - 0,1 )

=   10,25 x       10                     +  65 x       10,9

=         102,5                             +         708,5

=              811

= 46,125 + 65

= 111,125

a)=35x(34+38)+72x(65+65)

=35x72+72x130

=72x(35+130)

=72x165

=11880

ai nhanh nhất mình k cho

Bài 1:

\(A=\frac{1}{\left(1+2\right)}+\frac{1}{\left(1+2+3\right)}+\frac{1}{\left(1+2+3+4\right)}\)\(+\frac{1}{\left(1+2+3+4+5\right)}+...+\)\(\frac{1}{\left(1+2+3+...+10\right)}\)

\(A=\frac{1}{3}+\frac{1}{6}+....+\frac{1}{55}\)

\(A=2\left(\frac{1}{6}+\frac{1}{12}+....+\frac{1}{110}\right)\)

\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)

\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)

\(A=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)

\(A=\frac{9}{11}\)

Bài 2 :

2)  Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15

= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15

Mẫu số =  11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19  + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17  

=  (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x  17 = (1+27+125+729) x 13 x 15 x 17 

\(\Rightarrow A< \frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}\)

\(=\frac{11}{17}\)

\(=\frac{1111}{1717}=B\)

Vậy \(A=B\)

mình đâu biết

a) 35 x 34 + 35 x 38 + 65 x 75 + 65 x 45

  = 35 x (34+38)  + 65 x (75 + 45)

  = 35 x 72   +    65 x 120

  =  2520 + 7800 = 10320

b)  3 x 25 x 8 + 4 x 37 x 6 + 2 x 38 x 12

 = 3 x ( 25 x 8) + 4 x (37 x 6) + 2 x (38 x 12)

 = 3 x 200 + 4 x 222 + 2 x 456

= 600 + 888 + 912 = 2400

tk nha

35 x 34 + 35 x 38 + 65 x 75 + 65 x 45 

= 35 x ( 34 + 38 ) + 65 x ( 45 + 75 )

= 35 x 72 + 65 x 120

Vì quy tắc thực hiện tính toán phải làm nhân chia trước nên :

= (35 x 34)+(35 x 38)+(65 x 75)+(65 x 45)

= (1190 + 1330) + (4875 + 2925)

= 2520 + 7800

=10320

b) (3 x 25 x 8) +( 4 x 37 x  6) + (2 x 38 x 12)

= 600 + 888 + 912

= 2400

35 x 34 + 35 x 65 + 65 x 75 + 65 x 45

= ( 35 x 34 + 35 x 65 ) + ( 65 x 75 + 65 x 45 )

= 35 x ( 34 + 65 ) + 65 x ( 75 + 45 )

= 35 x 99 + 65 x 120

= 3465 + 7800

= 11265

\(35.34+35.65+65.75+65.45\)

=\(35.\left(34+65\right)+65.\left(75+45\right)\)

= 35. 99 +65.120

=3465 + 7800

= 11265

1)\(A=\frac{1}{3}+\frac{1}{6}+...+\frac{1}{55}=2\left(\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\right)=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\right)=2.\left(\frac{1}{2}-\frac{1}{11}\right)=\frac{9}{11}\)

2) Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15

= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15

Mẫu số =  11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19  + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 

lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 

=  (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x  17 = (1+27+125+729) x 13 x 15 x 17

=> \(A

giải giùm mình bài này vớC= (67/111+2/33-15/117)x(1/3-1/4-1/12)